Chemistry
A metal M forms a volatile chloride containing 65.5% chlorine. If the density of the chloride relative to hydrogen is 162.5, find the molecular formula of the chloride (M = 56).
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Answer
| Element | % composition | At. wt. | Relative no. of atoms | Simplest ratio |
|---|---|---|---|---|
| Metal M | 34.5 | 56 | = 0.616 | = 1 |
| chlorine | 65.5 | 35.5 | = 1.84 | = 2.98 = 3 |
Simplest ratio of whole numbers = M : Cl = 1 : 3
Hence, empirical formula is MCl3
Empirical formula weight = 56 + 3(35.5) = 162.5 g
Molecular weight = 2 x V.D. = 2 x 162.5 = 325
Molecular formula = n[E.F.] = 2[MCl3] = M2Cl6
∴ Molecular formula = M2Cl6
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