A jeweller claims that he makes ornament of pure gold of relative density 19.3. He sells a bangle weighing 25.25 gf to a person. The clever customer weighs the bangle when immersed in water and finds that it weighs 23.075 gf in water. With the help of suitable calculations find out whether the ornament is made of pure gold or not.

[Hint — Calculate R.D of material of bangle which comes out to be 11.6]

Given,

Relative density of pure gold = 19.3

Weight of the bangle in air (W₁) = 25.25 gf

Weight of the bangle in water (W₂) = 23.075 gf

$\text{Relative density of bangle} = \big(\dfrac{W${1}}{W{1} − W_{2}}\big) \\[0.5em] = \big(\dfrac{25.25}{25.25 - 23.075}\big) \\[0.5em] = \big(\dfrac{25.25}{2.175}\big) \\[0.5em] = 11.6

It is given that relative density of gold is 19.3 where as relative density of bangle is 11.6.

Hence, we can deduce that the bangle is not made of pure gold.