Chemistry
A hydrated salt contains Cu = 25.50%, S = 12.90%, O = 25.60% and the remaining % is water of crystallization. Calculate the empirical formula of the salt. [Cu = 64, S = 32, O = 16, H = 1]
Stoichiometry
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Answer
| Element | % composition | At. wt. | Relative no. of atoms | Simplest ratio |
|---|---|---|---|---|
| Cu | 25.50 | 64 | = 0.398 | = 1 |
| S | 12.90 | 32 | = 0.403 | = 1.01 = 1 |
| O | 25.60 | 16 | = 1.6 | = 4.020 = 4 |
| H2O | 100 - (25.50 + 12.90 + 25.60) = 36 | 18 | = 2 | = 5.025 = 5 |
Hence, Simplest ratio of whole numbers = Cu : S : O : H2O = 1 : 1 : 4 : 5
Hence, empirical formula is CuSO4.5H2O
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