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Chemistry

A gaseous compound of nitrogen and hydrogen contains 12.5% hydrogen by mass. Find the molecular formula of the compound if it's relative molecular mass is 37.

[N =14, H = 1].

Stoichiometry

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Answer

Element% compositionAt. wt.Relative no. of atomsSimplest ratio
Nitrogen100 - 12.5 = 87.51487.514\dfrac{87.5}{14} = 6.256.256.25\dfrac{6.25}{6.25} = 1
Hydrogen12.5112.51\dfrac{12.5}{1} = 12.512.56.25\dfrac{12.5}{6.25} = 2

Simplest ratio of whole numbers N : H = 1 : 2

Hence, empirical formula is NH2

Empirical formula weight = 14 + 2(1) = 16

Relative molecular mass = 37

n=Molecular weightEmpirical formula weight=3716=2.31=2\text{n} = \dfrac{\text{Molecular weight}}{\text{Empirical formula weight}} \\[0.5em] = \dfrac{37}{16} = 2.31 = 2

∴ Molecular formula = n[E.F.] = 2[NH2] = N2H4

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