A game of cards has cards marked with number x such that 9 < x ≤ 43. If a card is drawn at random, the probability of the number to be a perfect square is :

1. $\dfrac{1}{34}$

2. $\dfrac{3}{43}$

3. $\dfrac{3}{34}$

4. $\dfrac{40}{43}$

Cards (numbered) = {10, 11, 12, ……….., 43}

No. of possible outcomes = 34.

Favourable numbers of perfect square = {16, 25, 36}.

No. of favourable outcomes = 3

P(of getting a perfect square numbered card)

= $\dfrac{\text{No. of favourable outcomes}}{\text{No. of possible outcomes}} = \dfrac{3}{34}$.

Hence, Option 3 is the correct option.