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A cubical ice cream brick of edge 22 cm is to be distributed among some children by filling ice cream cones of radius 2 cm and height 7 cm up to its brim. The number of children who will get the ice cream cones is

  1. 163

  2. 263

  3. 363

  4. 463

Mensuration

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Answer

Edge of cubical ice cream brick (a) = 22 cm

Volume = a3 = (22)3 = 10648 cm3.

Radius of ice cream cone (r) = 2 cm and height (h) = 7 cm.

Volume of one cone = 13\dfrac{1}{3}πr2h

= 13\dfrac{1}{3} x 227\dfrac{22}{7} x 2 x 2 x 7

= 22×43\dfrac{22 \times 4}{3}

= 883\dfrac{88}{3} cm3.

Number of cones (n) = Vol. of ice cream brickVol. of cone\dfrac{\text{Vol. of ice cream brick}}{\text{Vol. of cone}}

n=10648883=10648×388=3194488=363.n = \dfrac{10648}{\dfrac{88}{3}} \\[1em] = \dfrac{10648 \times 3}{88} \\[1em] = \dfrac{31944}{88} \\[1em] = 363.

Hence, Option 3 is the correct option.

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