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A compound X [having vinegar like smell] when treated with ethanol in the presence of the acid Z, gives a compound Y which has fruity smell. The reaction is C2H5OH+XZY+H2O\text{C}2\text{H}5\text{OH} + \text{X} \xrightarrow{\text{Z}} \text{Y} + \text{H}_2\text{O}

(i) Identify Y and Z

(ii) Write the structural formula of X.

(iii) Name the above reaction

Organic Chemistry

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Answer

C2H5OHethyl alcohol+CH3COOHacetic acidConc. H2SO4CH3COOC2H5ethyl ethanoate+H2O\underset{\text{ethyl alcohol}}{\text{C}2\text{H}5\text{OH}} + \underset{\text{acetic acid}}{\text{CH}3\text{COOH}} \xrightarrow{\text{Conc. H}2\text{SO}4} \underset{\text{ethyl ethanoate}}{\text{CH}3-\text{COO}-\text{C}2\text{H}5} + \text{H}_2\text{O}

(i) Y is ethyl acetate and Z is conc. sulphuric acid

(ii) Structural formula of X (ethanoic acid) is shown below:

Write structural formula of ethanoic acid. Organic Chemistry, Simplified Chemistry Dalal Solutions ICSE Class 10.

(iii) Esterification reaction

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