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Chemistry

A compound with empirical formula AB2, has the vapour density equal to it's empirical formula weight. Find it's molecular formula.

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Answer

Empirical formula = AB2

Empirical formula weight = V.D.

Molecular weight = 2 x V.D.

n=Molecular weightEmpirical formula weightn=2 x V.D.V.D.n=2\text{n} = \dfrac{\text{Molecular weight}}{\text{Empirical formula weight}} \\[0.5em] \text{n} = \dfrac{\text{2 x V.D.}}{\text{V.D.}} \\[0.5em] \text{n} = 2

∴ Molecular formula = n[E.F.] = 2[AB2] = A2B4

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