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Chemistry

A compound has a formula = 'H2Y'. Y denotes a non-­metal. State the following:

  1. The electronic configuration of Y.
  2. The valency of Y.
  3. The bonding present in 'H2Y'
  4. The bonding present in the compound formed between potassium (1939K^{39}_{19}\text{K}) and 'Y'
  5. The formula of the compound formed between calcium (2040Ca^{40}_{20}\text{Ca}) and Y.

Chemical Bonding

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Answer

  1. The element Y needs 2 electrons to complete it's octet, so it will have 6 electrons in the outer most shell. Hence, will have 2, 6 as the electronic configuration. It is the electronic configuration of non-metal 'Oxygen'.
  2. 2 is the valency of element Y as it has 6 electrons in the outer most shell and needs two electrons to complete it's octet and attain a stable state.
  3. Covalent bond is present because each of hydrogen atom shares an electron pair with element Y such that hydrogen acquires a duplet configuration and Y an octet configuration and both become stable, hence form covalent bond.
  4. Ionic bond is present between potassium (1939K^{39}_{19}\text{K}) and 'Y' because K is a metal and Y is a non-metal.
  5. CaY is the formula for the compound formed between calcium (2040Ca^{40}_{20}\text{Ca}) and Y by transfer of two valence electrons. (As the electronic configuration of Y matches that of Oxygen so the actual formula will be CaO)

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