Mathematics
A closed rectangular box has inner dimensions 90 cm by 80 cm by 70 cm. Calculate its capacity and the area of tin-foil needed to line its inner surface.
Answer
Given,
Inner length of rectangular box = 90 cm
Inner breadth of rectangular box = 80 cm
Inner height of rectangular box = 70 cm
We know that
Capacity of rectangular box = volume of rectangular box = l × b × h
= 90 × 80 × 70
= 504000 cm3.
Area of tin foil = Surface area of box = 2(lb + bh + lh)
= 2(90 × 80 + 80 × 70 + 90 × 70)
= 2(7200 + 5600 + 6300)
= 2 × 19100
= 38200 cm2.
Hence, capacity of box = 504000 cm3 and area of tin-foil needed = 38200 cm2.
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