Chemistry
(a) Calculate the mass of ammonia that can be obtained from 21.4 g of NH4Cl by the reaction:
2NH4Cl + Ca(OH)2 ⟶ CaCl2 +2H2O + 2NH3
(b) What will be the volume of ammonia when measured at S.T.P?
Mole Concept
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Answer
(a) 107 g NH4Cl gives 34 g of NH3
∴ 21.4 g NH4Cl will give x 21.4
= 6.8 g of NH3
(b) Volume of ammonia produced by 107 g NH4Cl = 2 x 22.4 L
∴ Volume of ammonia produced by 21.4 g NH4Cl = x 21.4
= 8.96 L
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