A bus starting from rest moves with a uniform acceleration of 0.1 ms^-2 for 2 minutes. Find

(a) the speed acquired,

(b) the distance travelled.

(a) Given,

Initial velocity (u) = 0

Acceleration (a) = 0.1 ms^-2

Time = 2 minutes

Convert min into sec

1 min = 60 sec

So, 2 min = 2 x 60 sec = 120 s

v = u + at

Substituting we get,

v = 0 + (0.1 x 120) = 12

Hence, speed acquired = 12 ms^-1

(b) According to the third equation of motion,

2as = v² - u²

or

s = $\dfrac{\text{{v}}^2 - \text{{u}}^2}{2\text{a}}$

Since a = 0.1 ms^-2

v = 12 ms^-1

u = 0

t = 120 s

Substituting we get,

s = $\dfrac{{12}^2 - 0}{2 \times 0.1} = \dfrac{144}{0.2}$ = 720 m.

Hence, the total distance travelled is 720 m