Mathematics
A box contains a certain number of balls. On each of 60% balls, letter A is marked. On each of 30% balls, letter B is marked and on each of remaining balls, letter C is marked. A ball is drawn from the box at random. Find the probability that the ball drawn is :
(i) marked C
(ii) A or B
(iii) neither B nor C.
Probability
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Answer
Given,
On each of 60% balls, letter A is marked. On each of 30% balls, letter B is marked and on each of remaining balls (i.e. 10%), letter C is marked.
Let no. of balls be x.
∴ No. of possible outcomes = x.
No. of balls marked A =
No. of balls marked B =
No. of balls marked C = .
(i) No. of balls marked C or favourable outcomes =
P(drawing a ball marked C) = .
Hence, the probability of drawing a ball marked C = .
(ii) No. of balls marked A or B = .
P(drawing a ball marked A or B) = .
Hence, the probability of drawing a ball marked A or B = .
(iii) Since, the balls are marked either A, B or C.
So, P(drawing neither B nor C) = P(drawing A marked ball)
No. of A marked balls = .
∴ No. of favourable outcomes = .
P(drawing a ball marked A) = .
∴ P(drawing neither B nor C) = .
Hence, the probability of drawing ball marked neither B nor C = .
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