Physics

A body starts from rest with a uniform acceleration of 2 m s^-2. Find the distance covered by the body in 2 s.

Motion in One Dimension

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Answer

According to equation of motion —

S = ut + $\dfrac{1}{2}$ at²

Where,

distance covered = S

initial velocity u = 0

acceleration a = 2 m s^-2

time t = 2 s

Substituting the values in the formula for u = 0 , we get,

$S = (0 \times 2) + \dfrac{1}{2} \times 2 \times 2^2 \\[0.5em] S = (0) + (\dfrac{1}{2} \times 2 \times 4) \\[0.5em] S = (0) + (4) \\[0.5em] \Rightarrow S = 4 m \\[0.5em]$

Hence, distance covered = 4 m

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Physics

A body starts from rest with a uniform acceleration of 2 m s^-2. Find the distance covered by the body in 2 s.

Motion in One Dimension

Answer

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Physics

A body starts from rest with a uniform acceleration of 2 m s-2. Find the distance covered by the body in 2 s.

Motion in One Dimension

Answer

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