A bag contains six identical black balls. A child withdraws one ball from the bag without looking into it. What is the probability that he takes out:

(i) a white ball ?

(ii) a black ball ?

There are six identical black balls.

∴ No. of possible outcomes = 6.

(i) Since, there is no white ball.

∴ No. of favourable outcomes (of getting a white ball) = 0.

P(getting a white ball) = $\dfrac{\text{No. of favourable outcomes}}{\text{No. of possible outcomes}} = \dfrac{0}{6}$ = 0.

Hence, the probability of getting a white ball = 0.

(ii) There are 6 identical black balls.

∴ No. of favourable outcomes (of getting a black ball) = 6.

P(getting a black ball) = $\dfrac{\text{No. of favourable outcomes}}{\text{No. of possible outcomes}} = \dfrac{6}{6}$ = 1.

Hence, the probability of getting a black ball = 1.