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Mathematics

A bag contains 20 red balls, 12 blue balls and 8 green balls. Three balls are drawn one by one with replacement, the probability that the third ball being green is :

  1. 12\dfrac{1}{2}

  2. 25\dfrac{2}{5}

  3. 15\dfrac{1}{5}

  4. 1.8

Probability

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Answer

Total no. of balls = 20 + 12 + 8 = 40

No. of green balls = 8

Since, balls are drawn one by one with replacement.

∴ P(third ball drawn be green) = P(ball drawn to be green)

= No. of favourable outcomesTotal no. of possible outcomes=840=15\dfrac{\text{No. of favourable outcomes}}{\text{Total no. of possible outcomes}} = \dfrac{8}{40} = \dfrac{1}{5}.

Hence, Option 3 is the correct option.

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