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(a) An electric iron consumes energy at a rate of 880 W when heating is at the maximum rate and 330 W when the heating is at the minimum. If the source voltage is 220 V, calculate the current and resistance in each case.

(b) What is heating effect of electric current ?

(c) Find an expression for the amount of heat produced when a current passes through a resistor for some time.

Household Circuits

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Answer

(a) Given,

Power (P) = 880 W [when heating is at the maximum rate ]

Power (P) = 330 W [when heating is at the minimum rate ]

Voltage (V) = 220 V

Case I : When heating is at the maximum rate

We know,

P = VI

Substituting we get,

880 = 220 x I

I = 880220\dfrac{880}{220} = 4 A

From V = IR

Substituting we get,

220 = 4 x R

R = 2204\dfrac{220}{4} = 55 Ω

Hence, when heating is at the maximum rate, I = 4 A and R = 55 Ω

Case II : When heating is at the minimum rate

Substituting we get current (I)

330 = 220 x I

I = 330220\dfrac{330}{220} = 32\dfrac{3}{2} = 1.5 A

Substituting we get resistance (R),

220 = 1.5 x R

R = 2201.5\dfrac{220}{1.5} = 1.46 Ω

Hence, when heating is at the minimum rate, I = 1.5 A and R = 1.46 Ω

(b) When the electric circuit is purely resistive, that is, a configuration of resistors only connected to a battery; the source energy continually gets dissipated entirely in the form of heat. This is called heating effect of electric current.

(c) H = I2Rt where

This is known as Joule's law of heating.

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