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Chemistry

450 cm3 of nitrogen monoxide and 200 cm3 of oxygen are mixed together and ignited. Calculate the composition of the resulting mixture.

2NO + O2 ⟶ 2NO2

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Answer

2NO+O2⟶2NO22 vol.:1 vol.⟶2 vol.\begin{matrix} 2\text{NO} & + & \text{O}2 & \longrightarrow & 2\text{NO}2 \\ 2 \text{ vol.} & : & 1 \text{ vol.} & \longrightarrow & 2 \text{ vol.} \\ \end{matrix}

[By Gay Lussac's law]

1 Vol. of O2 reacts with = 2V of NO

200 cm3 oxygen will react with
= 200 × 2
= 400 cm3 of NO

∴ remaining NO is 450 - 400 = 50 cm3

NO2 = ?

1 Vol. of O2 produces 2 Vol. of NO2

∴ 200 cm3 of oxygen produces = 21\dfrac{2}{1} x 200 = 400cm3

Hence, NO2 produced = 400 cm3 and unused oxygen is 50 cm3, so total mixture = 400 + 50 = 450 cm3

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