Chemistry
2KClO3 ⟶ 2KCl + 3O2 ; C + O2 ⟶ CO2. Calculate the amount of KClO3 which on thermal decomposition gives 'X' vol. of O2, which is the volume required for combustion of 24 g. of carbon. [K = 39, Cl = 35.5, O = 16, C = 12].
Stoichiometry
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Answer
12 g of C requires 22.4 lit of O2
∴ 24 g of C will require x 24 = 44.8 lit. of O2
Hence, 24 g of C will require 44.8 lit of O2
67.2 lit of O2 is produced by 245 g of KClO3
∴ 44.8 lit of O2 is produced by x 44.8 = 163.33 g of KClO3
Hence, amount of KClO3 is 163.33 g.
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