Chemistry
112 cm3 of a gaseous fluoride of phosphorus has a mass of 0.63 g. Calculate the relative molecular mass of the fluoride. If the molecule of the fluoride contains only one atom of phosphorus, then determine the formula of the phosphorus fluoride. [ F = 19, P = 31]
Mole Concept
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Answer
Given,
112 cm3 of gaseous fluoride has mass = 0.63 g
so, 22400 cm3 of gaseous fluoride will have mass = x 22400
= 126 g
∴ Relative molecular mass of fluoride = 126 g
The molecular mass = At mass P + At. mass of F
126 = 31 + At. Mass of F
∴ At. Mass of F = 126 - 31 = 95 g
However, At. mass of F = 19
∴ = 5
So, 5 atoms of F, hence, the molecular formula = PF5
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