Chemistry

0.2 g atom of silicon combine with 21.3 g of chlorine. Find the empirical formula of the compound formed.

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Gram atom = $\dfrac{\text{Mass of element}}{\text{Atomic mass}}$

g atom of silicon = 0.2 = $\dfrac{\text{Mass of silicon}}{28}$

∴ Mass of silicon = 5.6 g and

Mass of chlorine = 21.3 g

Element	Mass	At. wt.	gram atoms	Simplest ratio
Silicon	5.6	28	$\dfrac{5.6 }{28}$ = 0.2	$\dfrac{0.2 }{0.2}$ = 1
Chlorine	21.3	35.5	$\dfrac{ 21.3}{35.5}$ = 0.6	$\dfrac{ 0.6 }{0.2}$ = 3

Simplest ratio of whole numbers = Si : Cl = 1 : 3

Hence, empirical formula is SiCl₃

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